[pct-l] (no subject)
mark v
allemande6 at yahoo.com
Sun Apr 13 01:12:34 CDT 2008
Steel-Eye, you're just being a pessimist. If one
doesn't have to carry days' worth of food or it's
packaging, the lighter pack weight would mean that a
full-time hiker would only require 4350 calories a
day. This means the hiker would merely have to catch,
clean, cook, and eat 30 trout per day. If it's a
hiker that appreciates sushi, then there is further
weight-reduction and time-savings, putting the total
in the upper 20s.
3.5 gallons of huckleberries? I'm so on it.
markv
> Good evening,
>
> A 10-inch trout will yield about 4 oz. of meat,
> which will provide 135
> Calories. If a full-time hiker required 4500
> Calories/day it would be
> necessary to catch, clean, cook, and eat 33 fish per
> day -- every day -- all
> while hiking 20 miles. Frankly, I didn't see that
> much good trout water
> anywhere near the trail.
>
> In the Pacific NW there will be trailside
> huckleberries, which provide about
> 80 Calories per cup. The need for 4500 Calories
> would require the hiker to
> pick and eat 3.5 gallons of berries every day.
> Picking that many berries
> would be time-consuming, but the real problem would
> be the time necessary to
> dig and fill about 15 cat-holes every day.
>
> Other than that - good luck,
>
> Steel-Eye
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